Selenium Finding elements by class name in python

You can try to get the list of all elements with class = content by using find_elements_by_class_name:

a = driver.find_elements_by_class_name(content)

Then you can click on the link that you are looking for.

As per the HTML:

<html>
    <body>
    <p class=content>Link1.</p>
    </body>
<html>
<html>
    <body>
    <p class=content>Link2.</p>
    </body>
<html>

Two(2) <p> elements are having the same class content.

So to filter the elements having the same class i.e. content and create a list you can use either of the following Locator Strategies:

Using class_name:

elements = driver.find_elements_by_class_name(content)

Using css_selector:

 elements = driver.find_elements_by_css_selector(.content)

Using xpath:

elements = driver.find_elements_by_xpath(//*[@class=content])

Ideally, to click on the element you need to induce WebDriverWait for the visibility_of_all_elements_located() and you can use either of the following Locator Strategies:

Using CLASS_NAME:

elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CLASS_NAME, content)))

Using CSS_SELECTOR:

elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, .content)))

Using XPATH:

elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, //*[@class=content])))

Note : You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

References

You can find a couple of relevant discussions in:

Selenium Finding elements by class name in python

The most simple way is to use find_element_by_class_name(class_name)