Python OpenCV2 (cv2) wrapper to get image size?

Python OpenCV2 (cv2) wrapper to get image size?

cv2 uses numpy for manipulating images, so the proper and best way to get the size of an image is using numpy.shape. Assuming you are working with BGR images, here is an example:

>>> import numpy as np
>>> import cv2
>>> img = cv2.imread(foo.jpg)
>>> height, width, channels = img.shape
>>> print height, width, channels
  600 800 3

In case you were working with binary images, img will have two dimensions, and therefore you must change the code to: height, width = img.shape

Im afraid there is no better way to get this size, however its not that much pain.

Of course your code should be safe for both binary/mono images as well as multi-channel ones, but the principal dimensions of the image always come first in the numpy arrays shape. If you opt for readability, or dont want to bother typing this, you can wrap it up in a function, and give it a name you like, e.g. cv_size:

import numpy as np
import cv2

# ...

def cv_size(img):
    return tuple(img.shape[1::-1])

If youre on a terminal / ipython, you can also express it with a lambda:

>>> cv_size = lambda img: tuple(img.shape[1::-1])
>>> cv_size(img)
(640, 480)

Writing functions with def is not fun while working interactively.


Originally I thought that using [:2] was OK, but the numpy shape is (height, width[, depth]), and we need (width, height), as e.g. cv2.resize expects, so – we must use [1::-1]. Even less memorable than [:2]. And who remembers reverse slicing anyway?

Python OpenCV2 (cv2) wrapper to get image size?

import cv2
import numpy as np

def main():
    # init cv
    cap = cv2.VideoCapture(0)

    while True:
        success, img =
# WAY 1
        img = cv2.flip(img, 1)

# WAY 2
            fwidth: {cap.get(cv2.CAP_PROP_FRAME_WIDTH)}, height: {cap.get(cv2.CAP_PROP_FRAME_HEIGHT)}, fps: {cap.get(cv2.CAP_PROP_FPS)})
        cv2.imshow(winname=universal control, mat=img)

if __name__ == __main__:

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