# python – How to clamp an integer to some range?

## python – How to clamp an integer to some range?

This is pretty clear, actually. Many folks learn it quickly. You can use a comment to help them.

``````new_index = max(0, min(new_index, len(mylist)-1))
``````
``````sorted((minval, value, maxval))[1]
``````

for example:

``````>>> minval=3
>>> maxval=7
>>> for value in range(10):
...   print sorted((minval, value, maxval))[1]
...
3
3
3
3
4
5
6
7
7
7
``````

#### python – How to clamp an integer to some range?

many interesting answers here, all about the same, except… which ones faster?

``````import numpy
np_clip = numpy.clip
mm_clip = lambda x, l, u: max(l, min(u, x))
s_clip = lambda x, l, u: sorted((x, l, u))[1]
py_clip = lambda x, l, u: l if x < l else u if x > u else x
``````
``````>>> import random
>>> rrange = random.randrange
>>> %timeit mm_clip(rrange(100), 10, 90)
1000000 loops, best of 3: 1.02 µs per loop

>>> %timeit s_clip(rrange(100), 10, 90)
1000000 loops, best of 3: 1.21 µs per loop

>>> %timeit np_clip(rrange(100), 10, 90)
100000 loops, best of 3: 6.12 µs per loop

>>> %timeit py_clip(rrange(100), 10, 90)
1000000 loops, best of 3: 783 ns per loop
``````

paxdiablo has it!, use plain ol python. The numpy version is, perhaps not surprisingly, the slowest of the lot. Probably because its looking for arrays, where the other versions just order their arguments.