javascript – freecodecamp Challenges- Seek and Destroy
javascript – freecodecamp Challenges- Seek and Destroy
You can create an array of all values that are supposed to be removed. Then use Array.filter
to filter out these values.
Note: Array.splice
will change original array.
function destroyer() {
var arr = arguments[0];
var params = [];
// Create array of all elements to be removed
for (var k = 1; k < arguments.length; k++)
params.push(arguments[k]);
// return all not matching values
return arr.filter(function(item) {
return params.indexOf(item) < 0;
});
}
console.log(destroyer([1, 2, 3, 1, 2, 3], 2, 3));
function destroyer(arr) {
/* Put all arguments in an array using spread operator and remove elements
starting from 1 using slice intead of splice so as not to mutate the initial array */
const args = [...arguments].slice(1);
/* Check whether arguments include elements from an array and return all that
do not include(false) */
return arr.filter(el => !args.includes(el));
}
console.log(destroyer([1, 2, 3, 1, 2, 3], 2, 3));
javascript – freecodecamp Challenges- Seek and Destroy
This worked for me:
function destroyer(arr) {
// Remove all the values
var args = Array.from(arguments);
var filter = [];
for (i = 0; i < args[0].length; i++) {
for (j = 1; j < args.length; j++) {
if (args[0][i] === args[j]) {
delete args[0][i];
}
}
}
return args[0].filter(function(x) {
return Boolean(x);
});
}
console.log(
destroyer([1, 2, 3, 1, 2, 3], 2, 3)
);
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