How to validate a url in Python? (Malformed or not)

Use the validators package:

>>> import validators
>>> validators.url(http://google.com)
True
>>> validators.url(http://google)
ValidationFailure(func=url, args={value: http://google, require_tld: True})
>>> if not validators.url(http://google):
...     print not valid
... 
not valid
>>>

Install it from PyPI with pip (pip install validators).

Actually, I think this is the best way.

from django.core.validators import URLValidator
from django.core.exceptions import ValidationError

val = URLValidator(verify_exists=False)
try:
    val(http://www.google.com)
except ValidationError, e:
    print e

If you set verify_exists to True, it will actually verify that the URL exists, otherwise it will just check if its formed correctly.

edit: ah yeah, this question is a duplicate of this: How can I check if a URL exists with Django’s validators?

How to validate a url in Python? (Malformed or not)

django url validation regex (source):

import re
regex = re.compile(
        r^(?:http|ftp)s?:// # http:// or https://
        r(?:(?:[A-Z0-9](?:[A-Z0-9-]{0,61}[A-Z0-9])?.)+(?:[A-Z]{2,6}.?|[A-Z0-9-]{2,}.?)| #domain...
        rlocalhost| #localhost...
        rd{1,3}.d{1,3}.d{1,3}.d{1,3}) # ...or ip
        r(?::d+)? # optional port
        r(?:/?|[/?]S+)$, re.IGNORECASE)

print(re.match(regex, http://www.example.com) is not None) # True
print(re.match(regex, example.com) is not None)            # False